1 solutions

  • 0
    @ 2025-3-3 16:27:11

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int t,n,a[100005],dp[100005];
    int main(){
        cin>>t>>n;
        for(int i=1;i<=n;i++)
        {
            cin>>a[i];
        }
        dp[0]=1;
        for(int i=1;i<=n;i++)
        {
            for(int j=a[i];j<=t;j++)
            {
                dp[j]=dp[j]+dp[j-a[i]];
            }
        }
        cout<<dp[t];
        return 0;
    }
    
    
    
    • 1

    Information

    ID
    10130
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    (None)
    Tags
    # Submissions
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