1 solutions

  • 0
    @ 2025-3-3 16:29:40

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    vector<int> a[100010];
    int n,m;
    int main(){
    	int i,j,x,y;
    	cin>>n>>m;
    	for(i = 0;i < m;i++){
    		cin>>x>>y;
    		//向下标为x-1的向量中存储y 
    		a[x-1].push_back(y);
    	}
    	
    	for(i = 0;i < n;i++){
    		sort(a[i].begin(),a[i].end());
    		cout<<a[i].size()<<" ";
    		for(j = 0;j < a[i].size();j++){
    			cout<<a[i][j]<<" ";
    		}
    		cout<<endl;
    		
    	} 
    }
    
    
    
    • 1

    Information

    ID
    10266
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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