1 solutions
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0
C++ :
#include <bits/stdc++.h> using namespace std; vector<int> a[100010]; int n,m; int main(){ int i,j,x,y; cin>>n>>m; for(i = 0;i < m;i++){ cin>>x>>y; //向下标为x-1的向量中存储y a[x-1].push_back(y); } for(i = 0;i < n;i++){ sort(a[i].begin(),a[i].end()); cout<<a[i].size()<<" "; for(j = 0;j < a[i].size();j++){ cout<<a[i][j]<<" "; } cout<<endl; } }
- 1
Information
- ID
- 10266
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By