1 solutions
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0
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ long long f[10] = {0};//存放0~9之间是否都出现了 long long c = 0;//存放1~9之间出现了几个数 long long n,k = 0,x,t,r; cin>>n; t = 1;//从1开始乘 //1~9如果还没都出现 while(c < 9){ k = n * t; r = k; while(k != 0){ x = k % 10; k = k / 10; //如果x还没出现,标记为出现了 if(x > 0 && f[x] == 0){ c++; f[x] = 1; } } t++; } cout<<r; return 0; }
Python :
n=int(input()) a=[0 for i in range(9)] js=0 while(a.count(1)<9): js=js+1 m=n*js m1=m while(m1>0): k=m1%10 if(k!=0): a[k-1]=1 m1=m1//10 print(m)
- 1
Information
- ID
- 10301
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By