1 solutions

  • 0
    @ 2025-3-3 16:32:50

    C :

    #include<stdio.h>
    
    int main()
    {
    	int n;
    	scanf("%d",&n);
    	int a[n],i,j,t,x;
    	for(i=0;i<n;i++){
    		scanf("%d",&a[i]);
    	}
    	scanf("%d",&x);
    	for(i=0;i<n-1;i++){
    		for(j=0;j<n-1-i;j++){
    			if(a[j]<a[j+1]){
    				t=a[j];
    				a[j]=a[j+1];
    				a[j+1]=t;
    			}
    		}
    	}
    	for(i=0;i<n;i++){
    		if(a[i]==x){
    			printf("%d",i+1);
    		}
    	}
    
    
    
    
    
    return 0;
    }
    
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    int main(){
    	int n,a[110],i,j,x;
    	//读入 
    	cin>>n;
    	for(i = 0;i < n;i++){
    		cin>>a[i];
    	}
    	cin>>x;
    	
    	//排序 
    	for(i = 1;i < n;i++){
    		for(j = 0;j < n - i;j++){
    			if(a[j] < a[j+1]){
    				swap(a[j],a[j+1]);
    			}
    		}
    	}
    	
    	//求名次 
    	for(i = 0;i < n;i++){
    		if(a[i] == x){
    			cout<<i+1<<endl;
    			break;
    		}
    	}
    	
    }
    
    

    Python :

    n=int(input())
    s=list(map(int,input().split()))
    s.sort(reverse=True)
    x=int(input())
    i=0
    while s[i]>x:
        i=i+1
    print(i+1)
    
    
    • 1

    Information

    ID
    10395
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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