1 solutions
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0
C :
#include<stdio.h> int main() { int a,b,c,i,s=0; scanf("%d%d%d",&a,&b,&c); if(a%b==0) { for(i=1;i<=a/b-1;i++) { if(((a-b*i)%c==0)&&((a-b*i)>=c)) { if((a-b*i)/c>=10&&i>=10) s++; } } printf("%d",s); } if(a%b!=0) { for(i=1;i<=a/b;i++) { if((a-b*i)/c>=10&&i>=10) s++; } printf("%d",s); } return 0; }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int i,n,x,y,t,c = 0; cin>>n>>x>>y; for(i = 10;i <= (n - y) / x;i++){ t = n - i * x; if(t % y == 0 && t / y >= 10){ c++; // cout<<i<<" "<<t / y<<endl; } } cout<<c; }
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner input = new Scanner(System.in); int n = input.nextInt(); int x = input.nextInt(); int y = input.nextInt(); int count = 0; for(int i = 10;i <= n - 10 * y / x;i++) { for(int j = 10;j <= n - 10 * x / y;j++) { if(i * x + j * y == n ) { count++; } } } System.out.println(count); } }
Python :
c = 0 s = input().split() n = int(s[0]) x = int(s[1]) y = int(s[2]) for i in range(1, n // x + 1): j = (n - i * x) // y if x * i + y * j == n and i >= 10 and j >= 10: c += 1 print(c)
- 1
Information
- ID
- 10541
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By