1 solutions

  • 0
    @ 2025-3-3 16:33:27

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    int n,dp[1001][1001],i,j,a[1001],b[1001];
    int main() {
    	cin>>n;
    	for(i = 1;i <= n;i++){
    		cin>>a[i];
    	}
    	
    	for(i = 1;i <= n;i++){
    		cin>>b[i];
    	}
    	
    	/*
    	  计算a序列取i个元素,b序列取j个元素下的最长公共子序列长度
    	*/ 
    	for(i = 1;i <= n;i++){
    		for(j = 1;j <= n;j++){
    			if(a[i] == b[j]){
    				dp[i][j] = dp[i-1][j-1] + 1;
    			}else{
    				dp[i][j] = max(dp[i-1][j],dp[i][j-1]);
    			}
    		}
    	}
    	
    	cout<<dp[n][n];
    	return 0;
    }
    
    • 1

    Information

    ID
    10586
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By