1 solutions
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0
C :
#include <stdio.h> void main() { int n; double p; scanf("%d",&n); if(n>=10) { p=n*2; }else{ p=n*2.2; } printf("%.1f",p); }
C++ :
#include <bits/stdc++.h> using namespace std; int main(){ int a; double b; cin>>a; if(a >= 10){ b = a * 2; }else{ b = a * 2.2; } cout<<fixed<<setprecision(1)<<b<<endl; return 0; }
Python :
n=int(input()) s=0 if n>=10 and n<=100: s=n*2 elif n<10 and n>0: s=n*2.2 print('%.1f' %s)
- 1
Information
- ID
- 10612
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By