1 solutions

  • 0
    @ 2025-3-3 16:33:39

    C :

    #include <stdio.h>
    int main(){
    int n,x,c;
    scanf("%d%d",&n,&x);    
    c=(n*1000)/x;
    if((n*1000)%x==0)
      printf("%d",c);
    else 
      printf("%d",c+1);
    }
    

    C++ :

    #include <bits/stdc++.h>
    using namespace std;
    
    int main()
    {
    	int n,x;
    	cin>>n>>x;
    	n = n * 1000;
    	cout<<(int)ceil(n * 1.0 / x)<<endl;
    
    	return 0;
    }
    

    Python :

    n,m = map(int,input().split()) 
    n=n*1000
    if n%m==0:
        print(n//m)
    else:
        print(n//m+1)
    
    
    
    • 1

    Information

    ID
    10618
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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