1 solutions
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0
C++ :
#include <iostream> using namespace std; int main() { int n ,i,j,k; cin>>n; for(i = 2; i < n; i++) { for(j = 2; j < n - i; j++) { k = n - i - j; if(i + j + k == n && i % 2 == 0 && j % 2 == 0 && k % 2 == 0 && i <= j && j <= k) { cout<<i<<" "<<j<<" "<<k<<endl; } } } return 0; }
Python :
n = int(input()) for i in range(1, n + 1): for j in range(1, n + 1): for k in range(1, n + 1): if i + j + k == n and i % 2 == 0 and j % 2 == 0 and k % 2 == 0 and i <= j <= k: print(str(i) + ' ' + str(j) + ' ' + str(k))
- 1
Information
- ID
- 10651
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By