1 solutions

  • 0
    @ 2025-3-3 16:33:40

    C++ :

    #include <iostream>
    using namespace std;
    
    int main(){
    	int max = 30 * 1200;
    	int p = 30;
    	int c = 1200;
    	int s;//售价 
    	int n;
    	cin>>n;
    	int price = p;//假设p元最划算 
    	while(c > 0){
    		p++;
    		c -= n;//每加1元,数量减少n张
    		s = p * c;
    //		cout<<p<<" "<<c<<" "<<s<<endl; 
            if(s > max){
            	max = s;
            	price = p;
    		}
    	}
    	cout<<price<<" "<<max<<endl;
    } 
    

    Python :

    n = int(input())
    x = 30
    y = 1200
    j = []
    m = []
    while(x <= y):
        z = x * y
        j.append(z)
        if(max(j) == x * y):
            m.append(x)
        x += 1
        y -= n
    print(max(m), max(j))
    
    • 1

    Information

    ID
    10664
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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