1 solutions
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0
C :
#include<stdio.h> #include<math.h> #include<string.h> struct ppppp { int sum; int k; } su[9999]; int main () { for(int i=0; i<9999; i++) su[i].sum=0; char p[999999]; scanf("%s",p); int n=strlen(p); p[n]='*'; int sum=0; int j=0; int flag=0,k; for(int i=0; i<=n; i++) { if(p[i]>='0'&&p[i]<='9') { if(flag==0) { flag=1; k=i+1; sum=sum+p[i]-'0'; su[j].k=k; } else { sum=sum*10+p[i]-'0'; } } else { if(sum!=0) { su[j].sum=sum; j++; sum=0; flag=0; } else { sum=0; flag=0; } } } int maxx=-100; for(int i=0; i<j; i++) { if(su[i].sum>maxx) { maxx=su[i].sum; k=su[i].k; } } printf("%d",k); return 0; }
Python :
str1=input() max = "0" # 存储值最大的数字 string = "" # 将连续的数字拼接起来 for i in range(1,len(str1)) : if str1[i-1].isdigit(): string += str1[i-1] else: if string == "": continue; elif int(string) > int(max): max = string string = "" print(str1.find(max) + 1)
- 1
Information
- ID
- 10716
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By