1 solutions

  • 0
    @ 2025-3-3 16:33:49

    C :

    #include<stdio.h>
    int main(){
    	int n,i,x;
    	scanf("%d",&n);
    	int a[n];
    	for(i=0;i<n;i++){
    		scanf("%d",&a[i]);
    	}
    	scanf("%d",&x);
    	for(i=x;i<=n-1;i++){
    		int t = a[i-1];
    		a[i-1] = a[i];
    		a[i] = t;
    	}
    	for(i=0;i<n;i++){
    		printf("%d ",a[i]);
    	}
    	
    	return 0;
    }
    

    C++ :

    #include <iostream>
    #include <iomanip>
    #include <cmath>
     
    using namespace std;
     
    int main(){
        int a[100],n,x,y;
        cin>>n;
        for(int i=0;i<n;i++){
        	cin>>a[i];
    	}
    	cin>>x;
    	for(int i=0;i<n;i++){
    		if(i+1!=x){
    			cout<<a[i]<<" ";
    		}else{
    		    y=a[i];	
    		}
    	}cout<<y<<endl;
    }
    

    Python :

    n=int(input())
    l1=list(map(int,input().split()))
    x=int(input())
    t=l1[x-1]  #先把第X个位置的数保存起来
    l1.remove(l1[x-1])
    l1.append(t)
    for i in l1:
        print(i,end=' ')
    
    • 1

    Information

    ID
    10751
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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