1 solutions
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0
C :
#include <stdio.h> #include <stdlib.h> /* run this program using the console pauser or add your own getch, system("pause") or input loop */ void main(int argc, char *argv[]) { int a[10]; int i,n,y; double s; s=0; scanf("%d",&n); for(i=0;i<n;i++){ scanf("%d",&a[i]); } for(i=0;i<n;i++){ s=s+a[i]; } for(i=0;i<n;i++){ if(s>100&&a[i]==a[n-1]) printf("%.2f",(s-100)*0.9+100); } }
C++ :
#include <iostream> #include <iomanip> #include <cmath> using namespace std; int main(){ int a[100],n,s=0,m,x; cin>>n; for(int i=0;i<n;i++){ cin>>a[i]; s+=a[i]; } cout<<fixed<<setprecision(2)<<100+((s-100)*0.9)<<endl; }
Python :
n=int(input()) l1=list(map(int,input().split())) def qiuHe(n): s=0 for i in l1: s+=i return s s=qiuHe(l1) if s>100: s=(s-100)*0.9+100 print('%.2f'% s) else: print(s)
- 1
Information
- ID
- 10752
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By