1 solutions

  • 0
    @ 2025-3-3 16:33:49

    C :

    #include<stdio.h> 
    
    int main(){ 
    	int n,m,i,j,k,temp; 
    	scanf("%d",&n);
    	scanf("%d",&m);
    	
    	
    	int a[m];
    	for(i = 0;i < m;i++){
    		scanf("%d",&a[i]);
    	} 
    	
    	int b[m+1];
    	for(i = 0;i < m;i++){
    		b[i] = a[i]; 
    	} 
    	b[m] = n;
    
    	for(i = 0;i < m;i++) {
    		k = i; //假设最小的值下标为i 
    		for(j = i + 1;j < m+1;j++){
    			if(b[j] < b[k]){   //如果需要从大到小排序  < 换 > 
    				k = j;
    			}
    
    		} 
    		
    		if(k != i){
    			temp = b[i];
    			b[i]  = b[k];
    			b[k] = temp;
    		}
    	
    	
    	} 
    	
    	for(i = 0;i < m+1;i++){
    		printf("%d ",b[i]);
    	}	
    	
    	return 0; 
    	  
    } 
    
    

    C++ :

    #include <iostream>
    #include <iomanip>
    #include <cmath>
     
    using namespace std;
     
    int main(){
        int a[100],n,x,y,i;
        cin>>x>>n;
        for(i=0;i<n;i++){
        	cin>>a[i];
    	}
    	for(i=0;i<n;i++){
    		if(a[i]<x){
    			cout<<a[i]<<" ";
    		}else{
    		    cout<<x<<" ";
    			break;	
    		}
    	}for(i=i;i<n;i++){
    		cout<<a[i]<<" ";
    	}
    }
    

    Python :

    n=int(input())
    m=int(input())
    l1=list(map(int,input().split()))
    
    for i in range(0,len(l1)):
        if n<=l1[i]:
            l1.insert(i,n)
            break
        if n>l1[m-1]:
            l1.append(n)
    for i in l1:
        print(i,end=' ')
    
    • 1

    Information

    ID
    10753
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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