1 solutions
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0
Python :
import math def suShu(n): f= True for i in range(2,int(math.sqrt(n)) + 1 ): if n % i == 0: f = False break return f and n != 1 def chaiwei(n): min = 0 # min 存放2段之和最小的素数 f = True # 表示是否为第一次获取素数 for i in range(1,len(n)): x = int(n[0:i]) + int(n[i:]) if suShu(x) : if f: min = x; f = False else: if x < min: min = x; return min n = input(); r = chaiwei(n) if r == 0: print(-1) else: print(r)
- 1
Information
- ID
- 10794
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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