1 solutions
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0
C :
#include<stdio.h> int main(){ int i,j; for(i = 1;i < 50;i++){ //i是鸡的数量 if(i * 2 + (50 - i) * 4 == 160){ printf("%d %d",i,50-i); } } return 0; }
C++ :
#include <iostream> using namespace std; int main(){ cout<<"20 30"<<endl; }
Python :
for r in range(0, 50): c = 50 - r cl = 2 * c rl = 4 * r if cl + rl == 160: print(c, r)
- 1
Information
- ID
- 10829
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By