1 solutions
-
0
C :
#include<stdio.h> main() { int a,m; m=(700000-28)/39; a=10*m+7; printf("%d\n",a); }
C++ :
#include <iostream> using namespace std; int main(){ cout<<179487<<endl; }
Python :
for i in range(100007,1000000): s=str(i) m1=s[0:5] num1=int(m1)*10+7 num2=700000+int(m1) if num2==4*num1: print (num1) break
- 1
Information
- ID
- 10870
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By