1 solutions

  • 0
    @ 2025-3-3 16:34:00

    C :

    #include<stdio.h> 
    
    
    int main(){ 
    	int n,i,j,z;
    	scanf("%d",&n);
    	//控制输出的行数 
    	for(i = 1;i <= n;i++){
    		//控制每行输出空格量 
    		for(j = 0;j < i - 1;j++){
    			printf(" "); 
    		}
    		//控住输出的*
    		for(z=1;z <= n;z++){
    			printf("*");
    		} 
    		//负责换行 
    		printf("\n");
    	}
    
    } 
    

    C++ :

    #include <iostream>
    using namespace std;
    
    int main(){
        int i,n,j;
        cin>>n;
        for(i=1;i<=n;i++){
        	for(j=1;j<=i-1;j++){
        		cout<<" ";
    		}
    		for(j=1;j<=n;j++){
    			cout<<"*";
    		}
    		cout<<endl;
    	}
    	
    }
    

    Python :

    n= int(input())
    for i in range (1, n + 1):
        for k in range (1,i):
            print(' ', end='')
        for j in range (1, n + 1):
            print('*', end = '')
        print();
        
    
    • 1

    Information

    ID
    10877
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
    0
    Accepted
    0
    Uploaded By