1 solutions

  • 0
    @ 2025-3-3 16:34:00

    C :

    #include<stdio.h> 
    
    
    int main(){ 
    	int n,i,j,z;
    	scanf("%d",&n);
    	//控制输出的行数 
    	for(i = n;i >= 1;i--){
    		//控制每行输出空格量 
    		for(j = 0;j < n-i;j++){
    			printf(" "); 
    		}
    		//控住输出的*
    		for(z=1;z <= 2 * i - 1;z++){
    			printf("*");
    		} 
    		//负责换行 
    		printf("\n");
    	}
    
    } 
    

    C++ :

    #include <iostream>
    using namespace std;
    int main (){
    	int i,j,n;
    	cin>>n;
    	char c;
    	for(i=n;i>=1;i--){
    		for(j=1;j<=n-i;j++){
    			cout<<" ";
    		}
    		
    		for(j=1;j<=i+i-1;j++){
    			
    			cout<<"*";
    		}
    		cout<<endl;
    	}
    }
    

    Python :

    n = int(input());
    for i in range(1, n + 1):
        for k in range(1, i):
            print(end=' ')
        for x in range(i ,2*n-i+1 ):
            print('*', end = '')
        print()
    
    
    • 1

    Information

    ID
    10880
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    (None)
    Tags
    # Submissions
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