1 solutions
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0
C :
#include<stdio.h> void main() { int x,a,b,i,j,c=0; scanf("%d%d%d",&x,&a,&b); for(i=1;i<x/a;i++){ j=(x-i*a)/b; if((x-i*a)%b==0&&i*a+j*b==x){ c++; } } printf("%d",c); }
C++ :
#include<iostream> using namespace std; int main(){ int x,a,b,i,f=0; cin>>x>>a>>b; for(i = 1;i <= x / a;i++) { if((x - i * a >= b) && (x - i * a) % b == 0 ){ f++; } } cout<<f<<endl; return 0; }
Python :
n = input().split() x = int(n[0]) a = int(n[1]) b = int(n[2]) c = 0 for i in range(1, x // a + 1): for j in range(1, x // b + 1): if a * i + b * j == x: c += 1 print(c)
- 1
Information
- ID
- 10891
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By