1 solutions

  • 0
    @ 2024-12-4 19:37:02

    C++ :

    #include<iostream>
    #include<cstdio>
    using namespace std;
    int main()
    {
    	int n;
    	cin>>n;
    	double fz=2,fm=1,sum=0;
    	for (int i=1; i<=n; i++)
    	{
    		sum+=fz/fm;
    		double t=fz;
    		fz+=fm;
    		fm=t;
    	}
    	printf("%.2lf\n",sum);
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题6.8

    Information

    ID
    2195
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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