1 solutions
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0
C :
#include<stdio.h> #include<math.h> int main() { int a[10]; int i,j,sum,n; for(i=0;i<9;i++) { scanf("%d",&a[i]); } scanf("%d",&n); for(i=0;i<9;i++) { if(n>a[i]&&n<a[i+1]) break; } for(j=0;j<=i;j++) printf("%d\n",a[j]); printf("%d\n",n); for(j=i+1;j<9;j++) printf("%d\n",a[j]); return 0; }
C++ :
#include<iostream> using namespace std; int a[11]; int main() { for (int i=1; i<=9; i++) cin>>a[i]; cin>>a[10]; for (int i=9; i>=1; i--) if (a[i+1]<a[i]) { int t=a[i+1]; a[i+1]=a[i]; a[i]=t; } for (int i=1; i<=10; i++) cout<<a[i]<<endl; return 0; }
- 1
Information
- ID
- 2201
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By