1 solutions
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0
C :
#include<stdio.h> int main() { int a,b; int flag=0; for(int i=1;i<=10000;i++) { for(int j=i+1;j<=10000;j++) { if((45*i+45*j-2*i*j)==0) flag++; } } printf("%d\n",flag); }
C++ :
#include <iostream> using namespace std; int main() { int a,b,cnt=0; for(a=1;a<10000;a++) { for(b=a+1;b<10000;b++) { if(2*a*b==45*(a+b)) cnt++; } } cout<<cnt; return 0; }
- 1
Information
- ID
- 2238
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By