1 solutions
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0
C :
#include<stdio.h> int main() { int N,n; int sum,i,z; while(~scanf("%d",&N)) { while(N--) { sum=0; z=0; scanf("%d",&n); for(i=1; i<=n; i++) { sum+=i; z+=sum; } printf("%d\n",z); } } return 0; }
C++ :
#include <stdio.h> int main() { int n,t; scanf("%d",&t); while(t--) { scanf("%d",&n); printf("%d\n",n*(n+1)*(n+2)/6); } }
- 1
Information
- ID
- 2241
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- (None)
- # Submissions
- 0
- Accepted
- 0
- Uploaded By