1 solutions

  • 0
    @ 2024-12-4 19:37:03

    C++ :

    #include<iostream>
    using namespace std;
    #define N 4
    int a[N]; 
    void f(int k)
    {
    	int i; 
    	if(k==N)
    	{
    		int sum=0;
    		for(i=0;i<N;i++)
    			sum+=a[i];
    		if(sum==1)//只有一个1 
    		{
    			if(!a[1]==a[3]&&!a[1]==a[2]&&!a[0]==a[1])
    			{
    				for (i = 0; i < N; i++)
    				{
    					if(a[i]) cout<<char('A'+i);
    				}
    			}
    		}
    		return;
    	}
    	for(i=0;i<2;i++)
    	{
    		a[k]=i;
    		f(k+1);
    	}
    }
    int main()
    {
    	f(0);
    	return 0;
    }
    
    

    Java :

    public class Main {
    	public static void main(String[] args) {
    		System.out.println("B");
    	}
    }
    
    • 1

    Information

    ID
    2272
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
    # Submissions
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