1 solutions
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0
C++ :
#include <iostream> using namespace std; #include <bits/stdc++.h> int zhuanhuan(char ch1[],char ch2[]){ int a,b; if(ch1[0]=='k'){ a=1000000; } if(ch1[0]=='m'&&strlen(ch1)==1||ch1[0]=='g'){ a=1000; } if((ch1[0]=='m'&&strlen(ch1)==2)){ a=1; } if(ch2[0]=='k'){ b=1000000; } if(ch2[0]=='m'&&strlen(ch2)==1||ch2[0]=='g'){ b=1000; } if((ch2[0]=='m'&&strlen(ch2)==2)){ b=1; } return a/b; } int main(){ int n,x; char ch1[5]; char ch2[5]; cin>>n; for(int i=1;i<=n;i++){ cin>>x; cin>>ch1; cin>>ch2; cin>>ch2; cin>>ch2; cout<<x<<" "<<ch1<<" "<<'='<<" "<<zhuanhuan(ch1,ch2)*x<<" " <<ch2<<" "<<endl; } }
- 1
Information
- ID
- 9159
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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