1 solutions
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0
C++ :
#include "bits/stdc++.h" using namespace std; int main() { int n,i,j,t=0; int a[30000],b[200]; scanf("%d",&n); for (i=1;i<=n;i++) { scanf("%d",&b[i]); a[b[i]]=1; } for(i=1;i<=n-1;i++) { for(j=i+1;j<=n;j++) { if(a[(b[i]+b[j])]==1) { a[b[i]+b[j]]=0; t=t+1; } } } printf("%d",t); return 0; }
- 1
Information
- ID
- 9189
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By