1 solutions

  • 0
    @ 2024-12-4 19:37:02

    C :

    #include<stdio.h>
    #include<math.h>
    int zong(int n)
    {
    	if(n==1)  return 1;
    	else return (zong(n-1)+1)*2;
    }
    int main()
    {
    	int n;
    	scanf("%d",&n);
    	int m=zong(n);
    	printf("%d",m);
    } 
    

    C++ :

    #include<iostream>
    using namespace std;
    int main()
    {
    	int n,sum=1;
    	cin>>n;
    	for (int i=1; i<n; i++)
    		sum=2*(sum+1);
    	cout<<sum<<endl;
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题6.10

    Information

    ID
    2197
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    (None)
    Tags
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